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```nginxingress_deployment = kubernetes.yaml.ConfigFile(
    "ingress-nginx",
    file = "./nginx-ingress.yaml",
    opts=oke_resource,
)```
Hello Everyone, We are deploying this resource *"nginxingress_deployment"* using *"kubernetes.yaml.ConfigFile"* function through python in pulumi kubernetes and the output is as expected. Along with this resource, we have another resources in place.

But, *Our Requirement is to*, We want to *Delete* only this resource "*nginxingress_deployment*" alone . This Resource needs to be deleted after creation of couple of resources in sequence.

Hence, Please suggest if there is any pulumi function that can be incorporated in the *pulumi python code as function* so that we can delete only this Resource alone without disturbing any other existing resources.