Also very disappointed in the quality of error messages - very poor - no idea where the problem could be coming from…

Found it: o_bucket_name = my_bucket.bucket.apply(lambda bk: f”MyBucket:{bk}“) o_bucket_name.apply(lambda v: log.info(f”Log:{v}“)) • I the above ‘v’ can be used as / is a normal string value. • Output will be in the Diagnostics section Still getting my head around Pulumi concepts etc, but it looks like the bucket name comes from the provider/API, not from state, hence the need for the lambda call to go get the info (but I hope I’m wrong). Also, at a very high level, it would appear you ‘drive Pulumi with Python’ rather than write Python code that includes Pulumi, but again, hope I’m wrong - early days yet… In the above, o_bucket_name is an output object that needs to go get the bucket name via lambda, even though you’ve already done a lambda on the name - not the anticipated behaviour of a string of “MyBucket:${bucket_name}“. Good luck!

print() works the same way as log.info, but as an output at the end, as per normal Python.