But the result is still of the type Output, isn't it? So I still can't get the underlying value from it
bored-river-53178
07/22/2019, 6:09 AM
I just don't understand why it's not possible to get values from the Outputs of another stack (which are already fully known and the start of 'pulumi up')
h
high-translator-22614
07/22/2019, 6:28 PM
Output.apply()
will call the function with the real value
high-translator-22614
07/22/2019, 6:29 PM
but i'm guessing what you actually mean is "`StackReference.get()` throws an error instead of returning an
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