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# general
s
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l
Unwrap seems to be a type, not a function. Are you casting an Output to an Unwrap? I'm a typescript newbie so I'm probably wrong, but I think that would be like saying "this thing is Unwrapped", rather than saying "Unwrap this thing".
Generally the way to get at wrapped outputs is to use
.apply()
on them.
b
I just need to get the unwrapped type, not to get unwrapped outputs, this is handled by the dynamic provider as described here https://www.pulumi.com/docs/intro/concepts/programming-model/#how-dynamic-providers-work
g
@bored-river-53178 can you share more about why you're trying to use the unwrapped type? Generally this isn't needed.
b
as I said, I want > to use it as an input in a dynamic provider