I am trying to get image name from the Image function from A

Question

I am trying to get image name from the Image function from Alpha s pulumi docker however whenever I call `ui image image name` it returns a `pulumi Output output object` which is expected however I need to insert the value as a string so I can create the container definition My question is how are you going about this I thought the following would work however it fails still Maybe its plain as day and I just been staring at it too long Error returns `Container image contains invalid characters `

faint-table-42725 · Answer

That s odd that it s still an `output` after you re within the apply

faint-table-42725 · Answer

Can you try passing the args to Output all as individual args instead of as an array

faint-table-42725 · Answer

My recollection is that output all in Python is actually variable arguments

faint-table-42725 · Answer

so you should either pass it as individual args or destructure the list e g ` arr`

faint-table-42725 · Answer

Ah yes it is <https www pulumi com docs reference pkg python pulumi pulumi Output all>

chilly-hairdresser-56259 · Answer

Yea I just switched it from `Output all arg1 arg2 arg3 apply ` same result

faint-table-42725 · Answer

So it still shows the output object w in your diff

chilly-hairdresser-56259 · Answer

yes

chilly-hairdresser-56259 · Answer

I tried a single arg same result

faint-table-42725 · Answer

What happens if you try just ui image image name apply

faint-table-42725 · Answer

If that does not work then can you please open an issue as a bug That doesn t sound right that apply on an output wouldn t actually do anything

chilly-hairdresser-56259 · Answer

Yea I just tested that out of curiosity still returns object class instead of the result

chilly-hairdresser-56259 · Answer

faint-table-42725 · Answer

Thanks and sorry about the trouble running into this