sparse-intern-71089
01/28/2021, 2:33 PMbillowy-army-68599
quiet-leather-94755
01/29/2021, 6:34 PMred-match-15116
02/18/2021, 12:01 AMOutput.all()
to create a dict. This is included in v2.21.0 of the SDK.
It is now possible to do the following:
Output.all(name=output1, name2=output2).apply(lambda x: x['name'])
billowy-army-68599