Hello all, How can I get properties of a Repository? When I use: ruri=repo.get(resource_name=reponame, id=repoid) The result is: ruri     : {    + arn             : “arn:aws:ecr:us-east-1:xxxx*:repository/my-repo*”    + encryption_configurations  : [    +   [0]: {        + encryption_type: “AES256"       }     ]    + id             : “my-repox”    + image_scanning_configuration: {      + scan_on_push: false     }    + image_tag_mutability    : “MUTABLE”    + name            : “my-repo”    + registry_id         : “xxxxxx”    + repository_url       : “xxxxx.dkr.ecr.us-east-1.amazonaws.com/my-repo-xxxxx”    + urn             : “urn😛ulumi:dev::gurney-python::aws:ecr/repository:Repository::my-repo” Then I used ruri.apply(lambda r: r[“repository_url”]) but I got this message: TypeError: ‘Repository’ object is not subscriptable So, how should I get the repository_url ?

I’m not sure what kind of resource it is but have you tried

r.repository_url

?

@prehistoric-activity-61023 is correct - https://www.pulumi.com/registry/packages/aws/api-docs/ecr/repository/#outputs

Thank you @prehistoric-activity-61023. Yes, your suggestion works. Actually with that there is no need for using “apply”. I can get it with ruri.repository_url directly.