Python How can I get a stack s config file path I know it s

Question

Python How can I get a stack s config file path I know it s `Pulumi lt stack gt yaml` but can I avoid hardcoding this If the last operation I do is `stack set all config ` I m looking to follow it up with something like `print stack lt config file path gt ` Is something like this available

bored-activity-40468 · Answer

Since this is automation api are you passing which env to the application

handsome-state-59775 · Answer

Hey sorry I don t quite understand what you mean by passing env to application If you mean environment variables then I m not at least explicitly referencing any in my program

bored-activity-40468 · Answer

Before automation api you d tell pulumi up via setting the stack or passing the config file With automation api how are you chosing which environment or stack to run

bored-activity-40468 · Answer

I m fairly new to Python but did some stuff and used the click command line library with automation api I d pass ` environment test` to the application and that s how I d determine which config to use

bored-activity-40468 · Answer

lemon-agent-27707 · Answer

< handsome state 59775> there are APIs to read and write the StackSettings object which corresponds to the stack yaml file You can see some examples in this test This doesn t give you the location of the file but does help you manipulate it

lemon-agent-27707 · Answer

Here is the impl of the underlying method You can use similar logic to get the file name if you need it <https github com pulumi pulumi blob master sdk python lib pulumi automation local workspace py L126 L135>

handsome-state-59775 · Answer

thanks i m resorting to similar logic for now my only concern was if in case Pulumi changes this logic in the future I may have a tough time debugging this