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#typescript
Title
# typescript
p

plain-night-8063

01/03/2020, 3:52 PM
Hello everyone! How can I create a few slightly different resources re-using an existing code as much as possible? For example, I need to create several Route53 records. However, a few of them are simple CNAMEs but others have failover policy. Is it possible to make the failover block dynamic? Thanks!
w

white-balloon-205

01/03/2020, 4:20 PM
Sure thing - you can fo something like
let failover = undefined; if (something) { failover = ...  } new Record(... { failover: failover });
g

glamorous-printer-66548

01/03/2020, 4:29 PM
how about something like this?
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function Record(type: string, record: string, failoverRoutingPolicies?: RecordFailoverRoutingPolicy[]) { return new aws.route53.Record(record, {
    records: [record],
    ttl: 300,
    type: "A",
    zoneId: aws_route53_zone_primary.zoneId,
});}
This then can be used like this:
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Record('A', '1.2.3.4');
Record('CNAME', '<http://foo.com|foo.com>');
Record('CNAME', '<http://blabla.com|blabla.com>', {somepolicy});
obviously my example isn't very useful in itself. but you get the idea: create a function which only accepts as args the 'non-common' things and hardcode the common things inside the function body.
if the failoverpolicy is the same across most entries, you can simply create it as const outside the function via
const policy = {mypolicy}
and then pass it to the function
p

plain-night-8063

01/03/2020, 4:50 PM
many thanks! I'm gonna try it