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You can compress a directory and push it up as an archive using

FileArchive

(https://www.pulumi.com/docs/intro/concepts/assets-archives/#archives)

Note that a folder may be passed to

FileArchive

to construct an archive from the contents of that folder. Also, both assets (single files) and archives (folders containing files) can be combined as part of building up an

AssetArchive

.

how can we use FileArchive to convert folder to a zip ? @great-queen-39697

as the docs explain, you pass the directory path as a string to the

FileArchive()

call. For example, if my folder is in the same directory as my code and is called

folder

, I would code the following in Python:

pulumi.FileArchive('./folder')

right, but it didnt pushed to S3 as .zip

ahh, I see what you're asking. Apologies. I don't know of a way to tell that call a specific output, so I'd use the compression library for your language of choice to compress the file, and then I'd pass that .zip file with

FileArchive

. So, for Python:

shutil.make_archive('myzip', 'zip', './folder')
....
pulumi.FileArchive('myzip.zip')

Thanks