Hey guys, pulumi.apply is running asynchronously while i need to make it run synchronously Scenario, i am trying to get the state of an existing service account

let resourceId : pulumi.Input<string> = "thx/".concat(sharedSecret.name); //"namespace/shared-keystore-jks-ksa" ;
let secrets: pulumi.Output<output.core.v1.ObjectReference[]> = k8s.core.v1.ServiceAccount.get("ksa-".concat(sharedSecret.name),resourceId).secrets;

Post retrieving the secret, i am trying to find the secret name and use the name to supply for further use

//works asynchronously
secrets.apply(v => {
            console.log("Secret Name ", v[0].name);
secretName_list.push(v[0].name);
        });
console.log(secretName);//print secret name

Complete program

1. var serviceAccountArray = [];
2. var secretName_list=[];
3. 
4. serviceAccountArray.forEach(ksa => {
5.     let resourceId : pulumi.Input<string> = "thx/".concat(ksa.name); //"namespace/shared-keystore-jks-ksa" ;
6.     let secrets: pulumi.Output<output.core.v1.ObjectReference[]> = k8s.core.v1.ServiceAccount.get("ksa-".concat(ksa.name),resourceId).secrets;
7. //running asynchronously
8. secrets.apply(v => {
9.          console.log("Secret Name ", v[0].name);
10.         secretName_list.push(v[0].name);
11.      });
12.  console.log(secretName_list); //print secret name empty because of apply
13. });

Line no. 10 get executed after line no. 12 at the end of the program while i wanted to wait for the execution to get it complete. Any idea how this can be sort out. Thanks!

Try not to do mutation of variables inside an apply! It is very very unlikely to work how you want. I would expect something like the following to build that array:

secretName_list = serviceAccountArray.map(ksa => {
    let resourceId : pulumi.Input<string> = "thx/".concat(ksa.name); //"namespace/shared-keystore-jks-ksa" ;
    let secrets: pulumi.Output<output.core.v1.ObjectReference[]> = k8s.core.v1.ServiceAccount.get("ksa-".concat(ksa.name),resourceId).secrets;
	secrets.apply(v => v[0].name);
 });

I ran the below code

var secretName_list = args.applicationSecrets.map(ksa => {
    let resourceId : pulumi.Input<string> = "thx/".concat(ksa.name); //"namespace/shared-keystore-jks-ksa" ;
    let secrets: pulumi.Output<output.core.v1.ObjectReference[]> = k8s.core.v1.ServiceAccount.get("ksa-".concat(ksa.name),resourceId).secrets;
    console.log("secrent name");
	secrets.apply(v => v[0].name);
})

console.log ("arraylist ",secretName_list);

It returns the array with undefined items looks like the apply executed later and array get populated with undefined value.

Oh sorry no I missed a return there. Switching languages all the time it's hard recalling the correct syntax without putting things through an IDE.

var secretName_list = args.applicationSecrets.map(ksa => {
    let resourceId : pulumi.Input<string> = "thx/".concat(ksa.name); //"namespace/shared-keystore-jks-ksa" ;
    let secrets: pulumi.Output<output.core.v1.ObjectReference[]> = k8s.core.v1.ServiceAccount.get("ksa-".concat(ksa.name),resourceId).secrets;
    console.log("secrent name");
	return secrets.apply(v => v[0].name);
})

Thanks Fraser but looks like it returns the function Output

arraylist  [
   OutputImpl {
     __pulumiOutput: true,
     resources: [Function (anonymous)],
     allResources: [Function (anonymous)],
     isKnown: Promise { <pending> },
     isSecret: Promise { <pending> },
     promise: [Function (anonymous)],
     toString: [Function (anonymous)],
     toJSON: [Function (anonymous)]
   },
   OutputImpl {
     __pulumiOutput: true,
     resources: [Function (anonymous)],
     allResources: [Function (anonymous)],
     isKnown: Promise { <pending> },
     isSecret: Promise { <pending> },
     promise: [Function (anonymous)],
     toString: [Function (anonymous)],
     toJSON: [Function (anonymous)]
   }
 ]

how would i get the value from it

You can't. There is no way to go from Output<T> to T, the only valid thing you can do with Outputs is pass them in as inputs to resources or export them as stack values.

Thanks Fraser, your solution work for me