I m building a list of kubernetes resources to make easier R

Question

I m building a list of kubernetes resources to make easier RBAC permissions resource deny instead of resource allow all except 1 so I ve made the following function however `jsonObj` isnt blank outside of the `output apply ` What am I doing wrong If I log it inside the `output apply ` it behaves as expected Some kind of scope thing I am not understanding I believe ```export function createRbacJson Generate list of valid resources names const getK8sApiOutput = new local Command get k8s api output create `kubectl api resources no headers o wide` const output = getK8sApiOutput stdout output apply v = gt console log v let jsonObj any = output apply row = gt row split n forEach function row const splitRow = row match ^ | ^ | ^ s + g if splitRow = null const resourceName = splitRow 0 if resource has a shortname skip it var columnModifier = 0 if splitRow length == 6 columnModifier++ const resourceApi = splitRow 1 + columnModifier const namespaced = splitRow 2 + columnModifier const resourceVerbs = splitRow 4 + columnModifier replace + g split + const verbs string = resourceVerbs forEach verb = gt verbs push verb console log resourceName console log resourceApi console log verbs console log namespaced jsonObj resourceName = api resourceApi verbs verbs namespaced namespaced const jsonObjOutput = pulumi output jsonObj return jsonObjOutput apply v = gt console log v ``` Output of `createRbacJson ` ``` ```

gorgeous-egg-16927 · Answer

An `apply` is a callback so it doesn t run at the same time as your other code it runs when the input is ready In this case your code basically skips the apply block and returns the empty result immediately You can fix this by returning the result of the `output apply` directly ```export function createRbacJson Generate list of valid resources names const getK8sApiOutput = new local Command get k8s api output create `kubectl api resources no headers o wide` const output = getK8sApiOutput stdout output apply v = gt console log v let jsonObj any = return output apply row = gt row split n forEach function row const splitRow = row match ^ | ^ | ^ s + g if splitRow = null const resourceName = splitRow 0 if resource has a shortname skip it var columnModifier = 0 if splitRow length == 6 columnModifier++ const resourceApi = splitRow 1 + columnModifier const namespaced = splitRow 2 + columnModifier const resourceVerbs = splitRow 4 + columnModifier replace + g split + const verbs string = resourceVerbs forEach verb = gt verbs push verb console log resourceName console log resourceApi console log verbs console log namespaced jsonObj resourceName = api resourceApi verbs verbs namespaced namespaced ```

glamorous-australia-21342 · Answer

wow awesome thanks

glamorous-australia-21342 · Answer

trying now

glamorous-australia-21342 · Answer

do i need an apply to get jsonObj Out that s what i wish to return from this function

gorgeous-egg-16927 · Answer

I think you could initialize it inside the apply and it would work like you want

glamorous-australia-21342 · Answer

so I tried your return method but it outputs an Output lt t gt

glamorous-australia-21342 · Answer

so then I tried this `console log createRbacJson apply v = gt v ` and its still an Output lt t gt

glamorous-australia-21342 · Answer

oh initialize the var to

glamorous-australia-21342 · Answer

how do you mean

gorgeous-egg-16927 · Answer

Oh your apply isn t returning anything You will need to return `jsonObj` from that

glamorous-australia-21342 · Answer

how sorry

gorgeous-egg-16927 · Answer

Something like this ```output apply row = gt row split n forEach function row const splitRow = row match ^ | ^ | ^ s + g if splitRow = null const resourceName = splitRow 0 if resource has a shortname skip it var columnModifier = 0 if splitRow length == 6 columnModifier++ const resourceApi = splitRow 1 + columnModifier const namespaced = splitRow 2 + columnModifier const resourceVerbs = splitRow 4 + columnModifier replace + g split + const verbs string = resourceVerbs forEach verb = gt verbs push verb console log resourceName console log resourceApi console log verbs console log namespaced return jsonObj resourceName = api resourceApi verbs verbs namespaced namespaced ```

glamorous-australia-21342 · Answer

oh right

glamorous-australia-21342 · Answer

i see

gorgeous-egg-16927 · Answer

Note the brackets around the function `apply input = gt return value `

glamorous-australia-21342 · Answer

oh yes i missed those

glamorous-australia-21342 · Answer

hmm but on the function call i get an ` apply` does not exit for type `void`

gorgeous-egg-16927 · Answer

Since you added an explicit return you also need to handle the `else` case

glamorous-australia-21342 · Answer

~i switched function return type to ` any` and `console log createRbacJson apply v any = gt v `~ nevermind

glamorous-australia-21342 · Answer

i dont want it to return jsonObj until the forEach is done

glamorous-australia-21342 · Answer

i think this is returning on every iteration of the forEach

glamorous-australia-21342 · Answer

i dont want to do anything if the row is null

glamorous-australia-21342 · Answer

i think i need it here

glamorous-australia-21342 · Answer

``` output apply row = gt row split n forEach function row const splitRow = row match ^ | ^ | ^ s + g if splitRow = null const resourceName = splitRow 0 if resource has a shortname skip it var columnModifier = 0 if splitRow length == 6 columnModifier++ const resourceApi = splitRow 1 + columnModifier const namespaced = splitRow 2 + columnModifier const resourceVerbs = splitRow 4 + columnModifier replace + g split + const verbs string = resourceVerbs forEach verb = gt verbs push verb console log resourceName console log resourceApi console log verbs console log namespaced jsonObj resourceName = api resourceApi verbs verbs namespaced namespaced return jsonObj ```

glamorous-australia-21342 · Answer

inside the new apply brackets

glamorous-australia-21342 · Answer

```const jsonObjOutput = pulumi output createRbacJson console log jsonObjOutput apply v = gt v ```

glamorous-australia-21342 · Answer

dang still printing as an output

glamorous-australia-21342 · Answer

``` OutputImpl pulumiOutput true resources Function anonymous allResources Function anonymous isKnown Promise lt pending gt isSecret Promise lt pending gt promise Function anonymous toString Function anonymous toJSON Function anonymous ```

billowy-army-68599 · Answer

you need to print the output inside the apply

glamorous-australia-21342 · Answer

right right

glamorous-australia-21342 · Answer

i just noticed haha

glamorous-australia-21342 · Answer

thanks

glamorous-australia-21342 · Answer

```TypeError Cannot read properties of undefined reading apply createRbacJson apply v any = gt console log v ```

billowy-army-68599 · Answer

no it needs to be sometjing liike ```jsonObjOutput apply v = gt console log v ```

glamorous-australia-21342 · Answer

``` undefined const jsonObjOutput = pulumi output createRbacJson jsonObjOutput apply v = gt console log v ```

glamorous-australia-21342 · Answer

< billowy army 68599> < gorgeous egg 16927>

billowy-army-68599 · Answer

if its undefined the apply isn t returning anything you l need to do some more debugging

glamorous-australia-21342 · Answer

if i replace the return with a console log jsonobj it prints out fine which is interesting

glamorous-australia-21342 · Answer

but then if i do console log createRbacJson its undefined

glamorous-australia-21342 · Answer

```export function createRbacJson any Generate list of valid resources names const getK8sApiOutput = new local Command get k8s api output create `kubectl api resources no headers o wide` const output = getK8sApiOutput stdout output apply v = gt console log v let jsonObj any = output apply row = gt row split n forEach function row const splitRow = row match ^ | ^ | ^ s + g jsonObj resourceName = api resourceApi verbs verbs namespaced namespaced console log jsonObj ``` Output ``` securitygrouppolicies api vpcresources k8s aws v1beta1 verbs delete deletecollection get list patch create update watch namespaced true ```

glamorous-australia-21342 · Answer

fyi all this trouble was because i didnt know `apply` needed a `return` in the function man facepalming