Hey team, I am new to Pulumi and I am stuck on one usecase where I want to show the user the actual property value in my stack trace. My current stack output is this:

Current stack outputs (1):
                              OUTPUT  VALUE
                                               vid     vpc-0515230c3d5f949a8

I am able to reference my stack using

stack_ref = pulumi.StackReference("PulumiPlay-dev")

but I am not sure how to print the value of vid now. I have tried using the

get_output

method but it is not returning anything.

stack_ref.get_output("vid") should return it

Or if you want the value from the command line:

pulumi stack output vid

I followed the automation API tutorial: https://github.com/pulumi/automation-api-examples/blob/main/python/inline_program/main.py In a different python file I am running this code:

import pulumi

stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: "https://" + s3_url
)}
print(obj)

The output that I am getting still shows me the object and not the value:

{'website_url': <pulumi.output.Output object at 0x109f9f2b0>}

Oh that's because

apply

always returns an Output object. If you did that print inside the apply function it would print the string value

I tried running this too. This is just giving me an empty response.

import pulumi

stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: f"https:// + {print(s3_url)}"
)}

That's not how print is meant to work:

stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: f"https:// + {s3_url}"
)}
obj["website_url"].apply(lambda s: print(s))

I'd expect that to print out the url