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stack_ref.get_output("vid") should return it

Or if you want the value from the command line: `pulumi stack output vid`

I followed the automation API tutorial: <https://github.com/pulumi/automation-api-examples/blob/main/python/inline_program/main.py>

In a different python file I am running this code:
```import pulumi

stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: "https://" + s3_url
)}
print(obj)```
The output that I am getting still shows me the object and not the value:
```{'website_url': &lt;pulumi.output.Output object at 0x109f9f2b0&gt;}```

Oh that's because `apply` always returns an Output object. If you did that print _inside_ the apply function it would print the string value

Also `Output.format("https://{0}", stack_ref.get_output("website_url"))` is probably a nicer way to do this rather than an apply

I tried running this too. This is just giving me an empty response.
```import pulumi

stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: f"https:// + {print(s3_url)}"
)}```

That's not how print is meant to work:
```stack_ref = pulumi.StackReference("inline_s3_project/dev")
obj = {"website_url": stack_ref.get_output("website_url").apply(
    lambda s3_url: f"https:// + {s3_url}"
)}
obj["website_url"].apply(lambda s: print(s))```
I'd expect that to print out the url