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# aws
s
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b
The ID in this case is just the bucket name. So your code should be
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bucket_sse = aws.s3.Bucket.get(
    resource_name = "dev-file-storage-sse",
    id = "dev-file-storage-sse"
)
g
Oh for * sake! I just assumed "id" meant arn without checking! Thanks!
b
🙂