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I think you can't use an Output as resource_name (with Python), but you can set the resource's `name` with an Output

I keep getting
```TypeError: Expected resource name to be a string```
I am trying
```self.rand = random.RandomId(
            self.resource_name(), byte_length=4, keepers={'target_port': target_port},
        ).hex
listener_kwargs = {
            'default_actions': [{'type': 'forward', 'target_group_arn': target_group.arn}],
            'load_balancer_arn': load_balancer.arn,
            'port': listener_port,
            'protocol': listener_protocol,
            'resource_name': pulumi.Output.concat(self.resource_name(), self.rand.hex),
        }```

where self.resource_name() returns a string

and name can't be set with the listener :man-shrugging:

Maybe this helps? <https://www.pulumi.com/docs/intro/concepts/resources/#autonaming>

resource names are static identifiers used by pulumi to build its internal graph, as `Output`s are dynamic (unknown until resolved), these can not be used to build a name