is it possible to handle the

KeyError

on an invalid

require_output

? if I do this:

try:
    foo = stack_output.require_output("doesnt_exist")
except KeyError:
    # whatever

the key error seems to be unhandled:

value = Output.all(Output.from_input(name), self.outputs).apply(lambda l: l[1][l[0]]) # type: ignore
    KeyError: 'doesnt_exist'
    error: an unhandled error occurred: Program exited with non-zero exit code: 1

Do you mean to use get_output instead since it's not guaranteed?

I actually just found that one, thanks 🙂